TERCER TAREA 1ª5 ALGEBRA T. MAT

I. ESCRIBIR LA ECUACIÓN CORRESPONDIENTE
1.- 73x
2.- x/15
3.- x/16
4.- 22-x
5.- x+34
6.- 7x-5
7.- x/3

II.- RESOLVER LAS SIGUIENTES IDENTIDADES

8.-(23/12)(15/7) - 24X = 64 -11X
(1.91)(2.14)-24x=64-11x
4.08-24x=64-11x
-24x+11x=64-4.08
-13x=59.92
x=59.92/-13
x=-4.60

9) 45 - (28/5) + 33/2 = 16X
45-5.6+16.5=16x
39.4+16.5=16x
55.9=16x
x=55.9/16
x=3.49

10) ((11/3)(45/7)/(26/9)(14/3))X + 25 -18 = 33
((3.6)(6.4)/(2.8)(4.6))x+25-18=33
(23.04)/(12.88)x+25-18=33
1.78x+25-18=33
1.78x=33-25+18
1.78x=26
x=26/1.78
x=14.60

11) 625-34 + (256/4) + 42X = 758 - 16/3
591+64+42x=758-5.3
655+42x=752.7
42x=752.7-655
42x=97.7
x=97.7/42
x=2.32

12) ((28/6)(47/3))X + (-2)(-4)(3) - (-2)(-3)(4)(6) = 16
(4.6)(15.6)x+24-144=16
71.76x=16-24+144
71.76x=136
x=136/71.76
x=1.89

13) ((17/4)(16/2)/(55/4)) + 25 -18 = 44 -33X
(4.25)(8)/(13.75)+25-18 = 44 -33X
(34)/(13.75)+25-18 = 44 -33X
2.47+25-18 = 44 -33X
2.47+25-18-44=-33x
-34.53=-33x
x=-34.53/-33
x=1.04

14) (11/18)- 23 + 2X = -17X + 29 - (13/21)
o.61-23+23+2x=-17x+29-0.619
0.61+2x=-17x+28.38
2x+17x=28.38-0.61
19x=27.77
x=27.77/19
x=1.46

15) 1236 - 458 + 478 -158X = 457 +(-2)(6)(7)(11)
1256-158x=457+(-924)
1256-158x=-467
-158x=-467-1256
-158x=-1723
x=-1723/-158
x=10.90